11R = √16 + 4 = √20
sin θ = sin (90 + B)
B is the angle betwwen the diagonal
Sin B = 2/2√5
Sin B = 1/√5
Cos B = 2/√5
Therefore
Sin θ = 2/√5
Torque = 100 * r* Sin θ
T = 100*2*2
T = 400Nm
maine kaha
there r a lot of tough problems on this site
lets give u some \lim_{n\rightarrow infinity}(very)^{n} simple problems on mechanics
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37 Answers
11
11then read carefully
THE NET TORQUE≠400N.m
BUT IT IS ZERO (0)
IT IS DUE TO THE FACT THAT r x f IS PERPENDICULAR TO THE SHEET AND ITS COMPONENT IS ZERO TOWARDS THE MOTION OF THE OBJECT
Γ=Iα
THIS EQUATION IS ONLY APPLICABLE WHEN THE TORQUE AND MOMENT OF INERTIA R TO BE FOUND ABOUT THE COM AND ALSO IN THAT CASE WHEN THE AXIS S STATIC AND AXIS IS PASSING THROUGH THE BODY