luks more like .... the linear density of string is 0.1 ..... therez no variable density acc. to ur wordings ...........
14 .. shud be 84 ............frm wat i interpreted ...
Paragraph for Questions numbers 14 to 16 :
Mass of a string varies with its length as m = 0.1L where m is in kg and L is in cm. A block of mass 5kg is hanging to its lower end. A force F = 12 N acts on the block in vertically downward direction as shown in the figure. The entire system is kept in an elevator which moves up with an acceleration of 2 m/s^2. Length of the string is 10 cm. Height of the elevator is 4m. Assume mass of (string + mass) system to be particle like at the point of interest. Take g = 10 m/s^2.
14. Tension at a distance 10 cm above the block is
(a) 60 N (b) 70 N (c) 72 N (d) 84 N
15. Force on the string from the ceiling of the elevator is
(a) 60 N (b) 70 N (c) 72 N (d) 84 N
16. Suppose the string connecting mass to ceiling of the elevator breaks at the point P (at ceiling; see figure) after some time but the force F continues to act. The acceleration of the (string + block) system just after the string breaks assuming (string + block) system to be particle is
(a) 2 m/s2 upward
(b) zero
(c) 10 m/s2 downward
(d) 12 m/s2 downward
hmm.. if the length is measured from top..... dun u think it will break ??
luks more like .... the linear density of string is 0.1 ..... therez no variable density acc. to ur wordings ...........
14 .. shud be 84 ............frm wat i interpreted ...
FOR SECOND PART U CAN CONSIDER A POINT MASS OF 6kg ... hangingin frm a massless thread ...
clearly tension = 6*12 + 12 = 84N ....
now at point of contact wit elevator..........R-T = 0 .......R=T=84N...
14 me 2 gettin 84.... but shayad koi trap ho sakta hai ......
iiti.... wata bt da rest of ur ans?