kcuh ni samjh ra

1 Answers

33
Abhishek Priyam ·

velocity of R is in tangential direction..

velocity of Q=2v/3
velocity of P=v/3

Now FBD of R

TQR=mv2/3l

TPQ=m(2v/3)2/2l+TQR

TOP=m(v/3)2/l+TPQ

Solving these..
TQR=mv2/3l
TPQ=5mv2/9l
TOP=2mv2/3

There fore
TOP:TPQ:TQR=3:5:6

hence b is the answer.

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