1@Nishant Sir...time of travelling should be equal na ???? (b) ? It's coming independent of θ .
7 Answers
62The first question is same as 10√3 velocity is 10√3/2i+15j
Look at it relative to the wedge.. the velocity will be -10√3/2i+15j
so it is same as projecting a stone along an incline at the angle of 60 degree with a velocity 10√3
62Q 3) think of it like this..
the length of each path is equal to 2R cos θ
while the acceleration is "____" fill in the blank and solve the question
[1]
1
23[Q2]
sp = vt
sq = at2/2
at any time t , distance between p and q i.e 'x'
is
x = at2/2 - vt + 40
(since at t = 0 x = 40 )
now when x is minimum
dx/dt = 0
since the slope of the curve formed by the eqn x = at2/2 - vt + 40
on the x-t graph will be zero
at - v = 0
thus t = v/a = 10 /2 = 5 sec
thus x is minimum at t =5 [ since double derivative = a = 2 = positive ]
thus at t = 5
x = 25 - 50 + 40 = 15
1for q1
http://targetiit.com/iit-jee-forum/posts/a-good-one-13177.html
