Mechanics - Kinematics-1

229

Dwijaraj Paul Chowdhury ·2013-02-25 23:30:20

30 m/s
The marble is thrown horizontally...since it is thrown // to x-axis
As
v=u+at
=10+(2*10)
= 30 m/s

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Akash Anand Wrong Answer..and approach as well, think in 3D
Upvote·0· Reply ·2013-02-26 03:46:12
Dwijaraj Paul Chowdhury Is the answer 10root 2?....because the motion of the projectile is in 2-D only
Upvote·0· Reply ·2013-02-26 05:09:41
Akash Anand No.. its again wrong
Upvote·0· Reply ·2013-02-26 05:49:51
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661

Gaurav Gardi ·2013-02-26 07:27:04

10root3

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996

Swarna Kamal Dhyawala ·2013-02-26 08:23:43

is the answer 10m/s

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Dwijaraj Paul Chowdhury How?
Upvote·0· Reply ·2013-02-26 09:00:44
Swarna Kamal Dhyawala sir wat is the answer to this question
Upvote·0· Reply ·2013-03-02 08:02:45
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535

Aditya Agarwal ·2013-02-26 12:01:37

10√(5-2âˆš2).
is this the answer?

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591

Akshay Ginodia ·2013-02-26 21:25:45

Is the answer 10m/s ??

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Akash Anand yeah ..this is the answer ..try to provide the solution
Upvote·0· Reply ·2013-03-03 22:11:10
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Soumyadeep Basu ·2013-02-26 21:27:31

Is the answer 10âˆš3 m/sec?

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1133

Sourish Ghosh ·2013-02-28 23:38:09

5√6 m/sec

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Shashank Agarwal ·2013-03-03 00:49:40

I think the answer is 10√3

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35

Rohit Chowdhuri ·2013-03-03 02:29:02

IS THE ANSWER 10/âˆš2.

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Akash Anand ·2013-03-03 22:12:06

The answer is 10 m/s. Now any one provide the solution.

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Anurag Ghosh ·2014-02-14 19:33:36

Sir my answer is coming as 10/root2,please provide the correct solution

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466

Himanshu Giria ·2014-02-14 20:19:28

it is 10 m/s ...
v_yis const. thruout = 10/√2
v_x is connst ant ly changing thru out
from 10/âˆš2 to -10/âˆš2 (v=â†’â‰¡u-gt)
so final magnitude is √(-a)²+ b² = √(a)²+ b²
=10 ms-1

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Himanshu Giria it wud effectivly b g x sin( theta=45 degree.) x t
Upvote·0· Reply ·2014-02-15 00:00:38
Himanshu Giria since v=u-gt is applicable for 1_D only ...
Upvote·0· Reply ·2014-02-15 00:01:35
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