Kinematics-6

we can see that the angle the vector makes from the vertican from it's point of origin is 45 degrees.

So, the magnitude of it's velocity after 2 seconds=
√(10*1/√2)² + (10.1/√2 - 10*2)²

= 14.736m/s
at an angle taninverse(1-2√2)°

The velocity vector makes an angle 90° with the x direction
So, velocity after time 2 sec=√(10*0)+(10*1-10*2)² =10m/s