The velocity vector makes an angle 90° with the x direction
So, velocity after time 2 sec=√(10*0)+(10*1-10*2)2 =10m/s
- Akash Anand Answer is correct but approach is wrong, try to understand the situation first.
we can see that the angle the vector makes from the vertican from it's point of origin is 45 degrees.
So, the magnitude of it's velocity after 2 seconds=
√(10*1/√2)2 + (10.1/√2 - 10*2)2
= 14.736m/s
at an angle taninverse(1-2√2)°
The velocity vector makes an angle 90° with the x direction
So, velocity after time 2 sec=√(10*0)+(10*1-10*2)2 =10m/s