1the total time needed for the happenings is 4 seconds.
to reach the maximum height-1sec.to reach the ground -2 seconds & to reach the initial position -1more sec.
hence 2d=4*10√2sin45° & d=20 m
A small ball is thrown from a height of 15 m above the ground and at a horizontal distance d from a vertical wall.The ball first hits the wall and then strikes the ground and then it flies back to its initial position of throwing.Take both collisions to be perfectly eleastic and neglect friction.The initial speed of the ball is 10√2m/s and angle of projection is 450 with the horizontal as shown.Find the horizontal distance of point of throwing from the wall 'd' in metres.(neglect air resistance and take g=10m/s2.
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