kinematics

a point moves in the x-y plane according to the relation x=a sin wt and y=a(1-cos wt) The distance travelled by a point during time T is

Please give solution

11 Answers

1
skygirl ·

area under the circle:

x2 + (y-a)2 = a2

[ acoswt=(...) , asinwt=(....) ... square n add.. ]

13
MAK ·

Vx = aw.coswt

Vy = aw.sinwt

=> V = a2w2

As velocity is constant... distance travelled in time T = V.T = a2w2.T...............

[1]

correct me if i'm wrong...

1
skygirl ·

distance= v'/' t ??

typoooooooooooo

13
MAK ·

edited... [1]

sorry for such a silly mistake... [2] ...... actually i forgot to switch on my brain after waking up... [6] [4]

1
skygirl ·

[1]

62
Lokesh Verma ·

@neo.mind..

you have made a small mistake it will be underroot of that expression

and also take care that it is the speed that is constant not velocity.

hence distance traveled will be speed times. time.

1
▬●๋•kể álwáýک● ·

[11]..bhaiya ,, mai kaha hu??..[11]
[12] [7] ...i mean..i 9 where am nw...but mai yaha kaha hu..[7]

33
Abhishek Priyam ·

@neo.mind..

:D :P

1
? ·

aw2T 2/ 2

1
▬●๋•kể álwáýک● ·

[2]...[2]

62
Lokesh Verma ·

hey neo.. sorry if it was not u.. but i think i replied to your post :)

May be it was mak's :)

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