24thoda bada likho bhai....[1]
TWO STONES ARE PROJECTED FROM A POINT P IN THE SAME DIRECTION WITH A VELOCITY OF 20m/s ONE AT ANGLE α ABOVE THE HORIZONTAL AND THE OTHER AT AN ANGLE α TO THE VERTICAL.FIND THE DISTANCE OF EACH STONE FROM P 1 SECOND AFTER PROJECTION AND THE DISTANCE THE STONES ARE APART.(COSα=4/5,SINα=3/5).
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5 Answers
621 second later
1st body:
u cos @ t, u sin @t - 1/2 gt2
2nd body:
u sin @ t, u cos @t - 1/2 gt2
substitute t=1 to get the vlaues
Distance between the two bodies is
√2 u (cos@ - sin@) t = 4√2
1BHAIYA,YOU HAVE GIVEN THE EXPRESSION FOR HORIZONTAL AND VERTICAL DISTANCES INDIVIDUALLY BUT IT IS NOT SO,READ THE QUESTION AGAIN,AND HOW DID YOU ARRIVE ON THE EXPRESSION OF DISTANCE BETWEEN THE TWO BODIES??
62well it is
u (cos@ - sin@) t and -√2 u (cos@ - sin@) t
in x and y direction respectively
thus the resultant will be root 2 times each!