a ball is dropped from a height. if it takes 0.200s to cross the last 6.00m before hitting the ground , find the height from which it was dropped ..(take g=10)
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1 Answers
62let the velocity during the start of the last .2 seconds is v
the final velocity is v+.2x10 = v+2
The distance travlelled is
(v+v+2)/2 x 0.2 = 6
v=29
now the initial velocity is 0
final velocity is v+2 = 31
time = 31/10
distance is 1/2(31+0).31/10 = 312/20
I hope i have not made any calculation error :)
