Kinematics

Q1) Four athletes are standing at the corners A,B,C and D of a square of side l.They simultaneously start running,such that A runs towards B,B runs towards C,C runs towards D and D runs towards A,each with velocity v.They will meet at O,after a time(where O is center of the square)
a) l/2v b)√2l/v
c)l/√2v c)l/v

Q2)If at a height of 40 m,the direction of a motion of a projectile makes an angle ∩/4 with the horizontal,then its initial velocity and angle of projection are respectively?

9 Answers

62
Lokesh Verma ·

In the first question, it is a standard question which you may have missed.

See the funda here is that the distance is L

the relative velocity VA/B is always v.

The time taken will be Relative distance by relative velocity = L/v

Another mistake hidden :P

62
Lokesh Verma ·

Q2)If at a height of 40 m,the direction of a motion of a projectile makes an angle ∩/4 with the horizontal,then its initial velocity and angle of projection are respectively?


At a height of 40m,

u cos 45 = vy(t) = √u2 sin2 45 - 2gh

Using this, find u

Mistake hidden :)

1
Honey Arora ·

how cn we find u using that eq.????
putting value of cos 45 and sin 45 the eq we get is
-2gh=0

62
Lokesh Verma ·

let intiatl velocity be uxi+uyj

Final yy can be found in terms of uy

Now at this time, the angle is 45 degree hence ux=vy

1
kapildhaka ·

Nishant your answer to 1st question is right but method is not correct. The relative velocity of A with respect to B is alway √2 v . Its the velocity of approach that is v and he has to approach a total distance of l so answer is l/v.

62
Lokesh Verma ·

yes you are right :P

1
kapildhaka ·

:P

1
Honey Arora ·

i don't think even this one is correct
as per soln given is book
At start the velocity of athlete at A is v along AB.The component of this velocity along AO
=v cosθ =v/√2
dist AO=1/2 AC=l/√2
so time taken =l/v

62
Lokesh Verma ·

honey what kapil has written is absolutely correct..

what is given in your book is also absolutely correct...

They are two different approaches.. and i like the approach of kapil..

This is also a stanadard approach which is there in many books.
(This is what i was trying to say .. but then this question has kind of become so standard that i overlooked the logic while typing ;)

Your Answer

Close [X]