kinematics ha

a particle located at x=0 and t=0 starts moving along a positive x axis with a veolcity v such that v=a√x/sqrt] whare A is a constant

q.1 HOW DOES THE VELOCITY VARY WITH TIME?

Q.2 WHAT IS THE AVERAGE VELOCITY OF THE PARTICLE OVER THE FIRST S METERES OF ITS PATH ?

2 Answers

v=aâˆšx/sqrt]

make dis clear.........

Q1)v=aâˆšx

dx/âˆšx=a.dt

integrating, we get

2âˆšx=at => x=a²t²/4

=> dx/dt= a²t/2 => v=a²t/4

Q2) avg. velocity = displacement/time = (S) / (2âˆšS/a)

=> V_avg = aâˆšS/2...

correct me if i am wrong !

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