a particle located at x=0 and t=0 starts moving along a positive x axis with a veolcity v such that v=a√x/sqrt] whare A is a constant
q.1 HOW DOES THE VELOCITY VARY WITH TIME?
Q.2 WHAT IS THE AVERAGE VELOCITY OF THE PARTICLE OVER THE FIRST S METERES OF ITS PATH ?
-
UP 0 DOWN 0 0 2
2 Answers
1Q1)v=a√x
dx/√x=a.dt
integrating, we get
2√x=at => x=a2t2/4
=> dx/dt= a2t/2 => v=a2t/4
Q2) avg. velocity = displacement/time = (S) / (2√S/a)
=> Vavg = a√S/2...
correct me if i am wrong !
