30\text{Let particles be A and B. Now apply relative velocity concept.}
\text{We find the rel. velocity of B wrt to A.}
V_{BA}=-50ms^{-1}
a_{BA}=10ms^{-2}
\text{Now use } s=ut+\frac{1}{2}at^{2} \text{. Put }s=125, u=V_{BA}\text{ and } a=a_{BA}.
Q. Two particles, one with constant velocity 50m/s and other with uniform acceleration 10m/s2, start moving simultaneously from the same place in the same direction. They will be at a distance of 125m from each other after how much time?
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6 Answers
3030Everything's done just calculate buddy. [1] If I'm not wrong, it comes to some thing like 5(1+\sqrt{2}) .
1i also got this ans but my teacher says that initial velocity of both the particles is 50m/s!!! how do i remove his misconcept
30Actually I realise I made a mistake.. The equation will be this:
\pm s= V_{BA}t + \frac{1}{2}a_{BA}t^{2}
You'll get two values of t.
t= 5s \text{ and the other one is } t=5(1+\sqrt{2})s.
1@manoj: i think u r the one who will give all the exams,not ur teacher....and this qstn is a bit ambiguous....though it seems that initial velocity of B = 0....