LAdder

take aA=4m/s2

vA=6m/s2

lenth of ladder as 16m

5 Answers

1
Unicorn--- Extinct!! ·

Use constraint.

1
Avirakt ·

can u give a detailed soln....

1
harsh jindal ·

CONSIDER WALL AS +Y AXIS & GROUND AS X AXIS
AS LENGTH OF LADDER IS CONSTANT
x^2+y^2=l^2
differentiate with respect to time
2x\frac{dx}{dt}+2y\frac{dy}{dt}=0
2xv_{x}+2yv_{y}=0
xv_{x}+yv_{y}=0
again differentiate w.r.t time
xa_{x}+ya_{y}+v_{x}^2+v_{y}^2=0
from this eqn find accelerations of both ends
after finding acceleration find their components perpendicular to rod

49
Subhomoy Bakshi ·

I loved this solution!!!

anyways look at this also..

http://www.targetiit.com/iit-jee-forum/posts/rotation-instantaneous-centre-of-rotation-12434.html

post no. #06

same soln tho...

1
harsh jindal ·

my calculation give angular acceleration \alpha =\frac{4}{26-9\sqrt{3}}

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