Use constraint.
5 Answers
harsh jindal
·2010-03-12 09:29:34
CONSIDER WALL AS +Y AXIS & GROUND AS X AXIS
AS LENGTH OF LADDER IS CONSTANT
x^2+y^2=l^2
differentiate with respect to time
2x\frac{dx}{dt}+2y\frac{dy}{dt}=0
2xv_{x}+2yv_{y}=0
xv_{x}+yv_{y}=0
again differentiate w.r.t time
xa_{x}+ya_{y}+v_{x}^2+v_{y}^2=0
from this eqn find accelerations of both ends
after finding acceleration find their components perpendicular to rod
Subhomoy Bakshi
·2010-03-12 09:50:20
I loved this solution!!!
anyways look at this also..
http://www.targetiit.com/iit-jee-forum/posts/rotation-instantaneous-centre-of-rotation-12434.html
post no. #06
same soln tho...
harsh jindal
·2010-03-12 09:50:45
my calculation give angular acceleration \alpha =\frac{4}{26-9\sqrt{3}}