466(B) 2 . 25 ms-2 eastward
Akash Anand Good WorkUpvote·0· Reply ·2013-06-26 03:55:54- Akash Anand Make sure you have the solution as well.
- Himanshu Giria Yes Sir
I have
2 Answers
466466force applied on block B BY SPRING = ma = 6*1.5 = 9 N
SINCE IT IS ideal spring , magnitude force applied on both ends is same
Therefore ,
ACCLN OF body A = F/m = 9/4 = 2.25 ms-2
Moreover the direction will be opp. since the sprinfg will try to come back to its original position and so hence it will pull both the objects i.e., the objects will move in the opp. direction
- Akash Anand Excellent Job ..keep it up