the pseudo force on m1 should balance m1gsin30.
m1acos30=m1gsin30
......a=gtan30......(1)
now,Mg-T=Ma.....(2)
T-(m1+m2)g=(m1+m2)a.......(3)
solve the eqns.......
I think the ans is Approx.6.85kg
In the figure mass m1=i kg and m2 = 4 kg. Find the mass M of the hanging block which will prevent the smaller block from slipping over the triangular block. All the surfaces are frictionless and the strings and the pulleys are light.
Buddy, have you drawn the correct F.B.D?
If you still can't get the correct answer, i'll post it.
the pseudo force on m1 should balance m1gsin30.
m1acos30=m1gsin30
......a=gtan30......(1)
now,Mg-T=Ma.....(2)
T-(m1+m2)g=(m1+m2)a.......(3)
solve the eqns.......
I think the ans is Approx.6.85kg