481sir iska answer plz mention kar dijiye.....
10 Answers
11sir,i think the acc of a and b should be same bcause they r connected by a common string
11Sir,if i consider b and c as a single body of mass total 3kg,then the ans is coming to be 3g/4(acc).i took it as a single body because b and a r connected by a common string
11sir,on solving further an equation is coming 3g/2=a+a2;where a is the acc of a and b(same) and a2 is the acc of c.
1161Well ..here is the answer ..
Acc. of block a = Acc. of block b = 3g/2 m/s2 (How?)
Acc. of block c = 0. (Why??????)
- Akash Anand Still waiting for the solutionUpvote·0· Reply ·2013-01-21 22:44:30
Prashant Kulthia 3g-T=a (for b)
T=a (for a)
by solving acc for both of them is 3g/2
and when initial acc net force on c is 0.
996the eqn for finding acc must be:
3g-T =1*a...............(1) (for block b)
T = 1*a....................(2) (for block a)
we get acc 3g/2 m/s2 for block a and b
and also the acc block c is =0 because there is no net force acting on it.
Sourish Ghosh Obviously there is net force on C.
1133Basically we can draw 3 FBDs for 3 different blocks. Assign tensions T1, T2, T3 from top to bottom, T3 being the tension in the spring. Then the eqns will be...
During equillibrium...
T1 = T2
T2 = T3 + 1g
T3 = 2g
After the string has been cut...
T2 = 1a1
1g + T3 - T2 = 1a2
2g - T3 = 2a3
a1 = a2 [ Both connected by same string]
Solving yields a1 = a2 = 3g/2 ; a3 = 0