mech

water drops fall at regular intervals from a roof.at an instant when a drop is about to leave the roof, the seperations between 3 succesive drops below the roof are in the ratio:

a)1:2:3
b)1:4:9
c)1:3:5
d)1:5:13

1 Answers

106
Asish Mahapatra ·

Let the drops fall after a time interval 't' before the successive drop.

Let drop 1 be now falling. Then drop 2 will have travelled for 't', drop 3 for '2t' and drop 4 for '3t'

S1 (dist of 2 from roof) = 0.5gt2
S2 (dist. between 2 and 3) = 0.5g(2t)2-0.5gt2 = 3*0.5gt2
S3 (dist. between 3 and 4) = 0.5g(3t)2-0.5g(2t)2 = 5*0.5gt2

So, S1:S2:S3 = 1:3:5

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