Mechanics-I

JEE Main 2015 Preparation › Mechanics questions › Mechanics-I

A uniform rod of mass M and length l is hinged about the mid point O so that it can freely rotate on OXY plane about the OZ axis. An impulse J is applied at the end of the rod as shown. The angular velocity of the rod, immediately after the impulse is applied, is

a) JMl b)6JMl c)12JMl d)3J2Ml

#Physics #Mechanics

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4 Answers

1

Vinay Arya ·2011-02-10 00:15:48

Dear Amit
We know that
Angular impulse =change in angular momentum
Jl/2=Iw=>w=J/2I
Hence (b)is the correct choice.

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1

EmInEm ·2011-02-10 00:23:07

I = ML²/12

J L/2 = ML²w/12

w = 6J/ML

vinay I is moment of inertia

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Vinay Arya ·2011-02-10 00:25:40

sorry.I thought the options are M.I.

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Amit Kumar ·2011-02-11 05:40:39

thnks.....i suppose ur method is correct..

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