Mechanics-I

BITSAT Preparation › Mechanics questions › Mechanics-I

A uniform rod of mass M and length l is hinged about the mid point O so that it can freely rotate on OXY plane about the OZ axis. An impulse J is applied at the end of the rod as shown. The angular velocity of the rod, immediately after the impulse is applied, is

a) JMl b)6JMl c)12JMl d)3J2Ml

#Physics #Mechanics

UP 0 DOWN 0 0 4
Post on FacebookPost anonymously?

4 Answers

1

Vinay Arya ·2011-02-10 00:15:48

Dear Amit
We know that
Angular impulse =change in angular momentum
Jl/2=Iw=>w=J/2I
Hence (b)is the correct choice.

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

EmInEm ·2011-02-10 00:23:07

I = ML²/12

J L/2 = ML²w/12

w = 6J/ML

vinay I is moment of inertia

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

Vinay Arya ·2011-02-10 00:25:40

sorry.I thought the options are M.I.

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

Amit Kumar ·2011-02-11 05:40:39

thnks.....i suppose ur method is correct..

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω