I = ML2/12
J L/2 = ML2w/12
w = 6J/ML
vinay I is moment of inertia
A uniform rod of mass M and length l is hinged about the mid point O so that it can freely rotate on OXY plane about the OZ axis. An impulse J is applied at the end of the rod as shown. The angular velocity of the rod, immediately after the impulse is applied, is
a) JMl b)6JMl c)12JMl d)3J2Ml
Dear Amit
We know that
Angular impulse =change in angular momentum
Jl/2=Iw=>w=J/2I
Hence (b)is the correct choice.