same post..
http://targetiit.com/iit_jee_forum/posts/mistake_where_2582.html
Dont know where I am wrong.......
I solved this question by 2 diff methods and am getting answers diff.....plzz tel my mistake
Q A sphere of 5 kg specific gravity 2 is completely submerged into water.Find radius of sphere
method 1
Volome of sphere=mass /density =5/(2*103)=4/3 πr3
=>r=√(15*10-3/8π )
method2
Upthrust=Gravity
=>VÏwg=mg
=>(4/3 πr3)(103)=5
=>r=√(15*10-3/4π)
where is the mistake?????????[7][7][7]
maybe because they haven't given that it is in equlibrium or something ,u can't use method 2,
what if the sphere lies at the bottom ??
yaar upthrus = weight only when its just floatin or sp. gravity is 1!!!!!!!!!!!!!!!!
so method 2 is rong!!!!!!!!!!!!!![2]................................
method 1 luks all right just make sure ur units ar right and ull get the answer!!!!!
same post..
http://targetiit.com/iit_jee_forum/posts/mistake_where_2582.html
eureka must have double clicked on the "add topic" button.....happens a lot of times [4]
yaa its double post...................priyam and ashish already helped me there.........but thanx again.[1][1]