1
Shreyan
·2008-11-07 09:21:12
moment of inertia of a ring about an axis parallel to axis passing through centre and through the circumference:
using parallel axis theorem,
Ixx' = Ic + Md2
Ixx' = Mr2 + Mr2 = 2Mr2
thus, moment of inertia is more than MR2
(is this what u actually asked for???)
39
Dr.House
·2008-11-07 19:24:18
that answer was too obvious yaar shreyan.i want some physical situation without any use of these parallel axis theorem.
62
Lokesh Verma
·2008-11-07 19:29:19
Hmm.. this is a still better question :)
1
Grandmaster
·2008-11-20 07:04:46
u can see the moment of inertia of a ring alontg its srim von vertical axis
62
Lokesh Verma
·2008-11-20 07:16:08
Finally Am posting the answer cos no one else did :) (Sorry b555.. and sorry i dont know ur name either :D)
This is not a very easy visualisation....
take a Sphere of variable density.. very high density at the center and lower density as you go out.. Find the I of this..
Or for that matter an Atom.. The Protons and Neutrons at the center and electrons aroudn it..