I=√3/5*m*l^2
how to find moment of inertia of rod shown above about the axis passing through its mid-point at an angle 60 degree(shown in black line)
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UP 0 DOWN 0 0 7
7 Answers
Samarth Kashyap
·2009-06-19 20:48:10
i'm getting it as ml2/4
i'm not sure
λ=m/2l
I=2∫λ(xsin600)2dx between the limits 0 and l
JOHNCENA IS BACK
·2009-06-20 06:46:53
well mr nobody u could have usewd limits instead as -l to l.....[1]
Samarth Kashyap
·2009-06-20 06:53:45
yeah, its either 2∫... between 0 and l
or ∫.... between -l and l