Momentum imparted

JEE Main 2015 Answers › Mechanics questions › Momentum imparted

A ball falls vertically onto a floor, with momentum p, and then ball bounces repeatedly. The coefficient of restitution is e. The total momentum imparted by ball to the floor is
A) p(1 + e)
B) p/(1 - e)
C) p(1 + 1/e)
D) p{ (1+e) / (1 - e)}

#Physics #Mechanics

UP 0 DOWN 0 0 3
Post on FacebookPost anonymously?

3 Answers

Sunil Kumar ·2009-02-18 23:20:59

i think the answer is d.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Amit Jha ·2009-02-18 23:28:09

The answer is correct but how?

UP 0 DOWN 0
Post on FacebookPost anonymously?

Sunil Kumar ·2009-02-19 00:07:23

here is the solution to ur question amit....

When a particle goes normal collision with the floor with restitution coefficient e, the speed after collision is e times the speed before collision.
Thus here, the change in momentum for 1st impact is ep - (-p) = p(1 + e),
for 2nd impact it is e(ep) - (-ep) = ep(1 + e) and so on...

Hence the total change in momentum is given by
p(1 + e)[ 1 + e + e² .............]
= p (1 + e)/ (1 - e)

Hope u got it......

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

Momentum imparted

3 Answers

Your Answer

Add Image

Similar Questions