momentum

A small bucket of mass M is attached to a long inextensible cord of length :L as shown in fig. The bucket is released from its lowest position, the bucket scoops up mass m and swing to a height h. The height h is
A. LM2 / (M+m) 2
B. Lm2 / (M+m) 2
C. LMm / (M+m) 2
D. LMm / (M-m) 2

3 Answers

1
aditya chatterjee ·

A

1
varun.tinkle ·

easy sum vel at the bottom most pnt is root 2gl
since its an inelastic collision new vel is M√2gl/M+m
now hieght reached can be found from the kinematics equations v^2=U^2-2gh

1
pratik123 agrawal ·

answer is b.there is some aditional answer with b.that is m^l/(M+m)^2

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