MORE THAN 1 RIGHT - ROLLING!

IIT JEE 2015 Forum › Mechanics questions › MORE THAN 1 RIGHT - ROLLING!

a solid cylinder of mass M is rolled horizontally on a rough surface with a force F acting on centre of mass (actually there is a diag but has just a cylinder horizontally rolling and F is acting towards right from centre.Then

a) accn of COM is F/M

b)accn of COM is F2M

c) the force of friction acts backward on the cylinder

d) magnitude of force of friction is F3

note F acts towards right>

#Physics #Mechanics

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4 Answers

pranav ·2010-03-05 00:08:50

???????????

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pranav ·2010-03-05 00:50:09

plzzz

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Bicchuram Aveek ·2010-03-05 01:09:18

ans: c and d.

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govind ·2010-03-05 03:55:01

The answer shud be C and D
let f_r be the frictional force..
draw the fbd and u will notice that f_r is acting backwards..
F - f_r = Ma balancing of forces
f_r.R = MR²Î±/ 2 torque eqⁿ
f_r = Ma/2 since pure rolling so a = RÎ±
F = 3Ma/2
acceleration of centre of mass = 2F/3M

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MORE THAN 1 RIGHT - ROLLING!

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