new method to solve a sum

see i hv two methods to solve this sum

first the conventional method in most buks u must be knowing relativ vel concept if not .... nudge me

kkkk

my method

at time t th enorth moving ship has moved a distance 40 t and the west moving ship has moved 40t......

now draw a right angled trinagle..... so its hypo is the distance .......

which is equal to...x^2=10=40t ^2 =40t^

for minimum value differentiate it leaving it as an excersice...

now u know the value fo t u can find out distance

good job, dude

though I think that the expression should read
x²=(10-40t)²+ (40t)²