Two cars A and B are moving in the same direction with the uniform velocities of 40km/hr and 30km/hr respectively. They are separated by a distance of 5km. Another car C moving in the oppostie direction with a velocity of 25km/hr meets B when car A overtakes B. What is the initial distance of separation between cars A and C(now edited :))
A pretty long question but very easy try and post
1I think the question must be "what's the initial seperation b/w A and C". since initial seperation b/w A and B is already given in question. !
Time after which A overtakes B = 5/(40-30) = 0.5 hr.
Distance travelled by C in this time = (30+25)x0.5 = 27.5 km.
Hence initial seperation b/w A and C will be 27.5+5 = 32.5 km.
correct me if i am wrong !
1i think if u meant , the initial distance between A and C , it;ll come out to be 70km
11sorrry for the typo it is initial separation between A and C
it too got 32.5 km and felt it was right
but answr given is 17.5(again editing here i feel im sleepy)
11this was the solution given
it is similar to The Race's solution till 0.5hr
then during this time car C moves a distance of 25x1/2=12.5km
so initial separation between B and C is 12.5km There fore distance of C from A initially is 5+12.5=17.5
1That's completely wrong !!!
car B is not stationary. it is also moving towards C, so we must consider the relative velocity VCB and not just VC
our answer is correct subash. :)