11mgh = mv2/2
v = √2gh
v= √2*10*50
v =√1000
9 = 1000 - 2*2*S
4*S = 991
S = 991/4
S = 247.75
He was bail out at 297.75 m
a parachutist after bailing out falls 50m without friction wen parachute opens it decelerates at 2m/s2 he reaches d ground with a speed of 3m/s at what height did he bail out?
d equation of d straight line wich bisects d intercepts made by d axes on d lines x+y=2 & 2x+3y=6 is?
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15 Answers
1111x + y = 2 & 2x + 3y =6
Intercepts (1)
2,0
0,2
Intercepts (2)
3,0
0,2
The points of the st line is (0,2) & (2.5,0)
Slope = 2/-2.5
y - 2 = 2(x)/-3.5
-2.5y + 5 = 2x
-5y + 10 = 4x
4x + 5 y = 10---------------answer
11See
v2 = u2 + 2*a*S
9 = 1000 - 4S
S = 991/4
This is considering g = 10
if g= 9.8
9 = 2*9.8*50 - 4S
4S = 971
S = 242.75
Total = S + h = 242.75 +50
T = 292.75m
11Brinda pls provide us with a answer Pls donot leave us in dark
62a parachutist after bailing out falls 50m without friction wen parachute opens it decelerates at 2m/s2 he reaches d ground with a speed of 3m/s at what height did he bail out?
the answer is not very tough...
502=2x10.t
t=25 seconds
Till then the velocity has become 250 m/s
Now the deceleration is 2 ..
final velocty is 3..
so the time is 247/2 = 123.5 seconds
The total distance travelled = 1/2 x 10 x 252 + 1/2(250+3)x123.5
This should give the answer..
62d equation of d straight line wich bisects d intercepts made by d axes on d lines x+y=2 & 2x+3y=6 is?
(1,1) and (3/2, 1)
The line should pass through these two..
The line is indeed y=1
your answre is correct :)