3hi rashi ...............
""inelastic""" means the particle stops moving along the radial direction and its velocity is same along the tangential direction ..........................
[why because its completely inelastic and the common tanget is along radial dir.]
its R/2 ABOVE THE CENTER ............
draw a right angle triangle joining the point of collision center and drop a prependicular frm the point of collision to the horizontal radius [hope can visualise] ......
now u get the angle betw the horizontal and tangetial dir. as 60 ............
therefore vel. after collision is 10cos(60) = 5m/s ............
part 2 .....
m/10(5/2) + mv = m/10(5) .......
mv =m/10(5/2) ...
v = 1/4 .................. [not machin[2]] ......but ashish it dosnt stick to the shpere so
[M + M/10] is rong ..........
conserving ang. momentum
M/10(10)(R/2) = M/10(5/2)(R/2) + (2/5MR2)W .......
(1/10)(5/2)(1/2) = 2/5R(W) ..........
1/8 = 2/5RW .....
50/16 = W ..[AGAIN NOT MACHIN [2]]