an object of mass 5kg is projected with v=20m/s at angle of 60 wit d horizontal .at highest point of its path d projectile explodes and breaks into 2 fragments of mass 1kg and 4kg.they separate horizontally.the explosion releases internal energy such tat K.E of system is doubled.calculate separation between 2 fragments wen dey reach the ground
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2 Answers
49velocity at highest point before explosion=20cos 60°=10 m/s..
before explosion, energy=12X5X102 J
after collision, energy=5X102 J
now vel of 4 kg part=V and 1 kg part=v
so, 5X10=4V-v
124V2+12v2=500
now the second case will be when we ll consider the case wer 1 kg mass flies in direction of projectile motion b4 explosion...
i e we ll write 5X10=v-4V
49next time to fall is time for free fall ie half the time of flight for the original projectile..[1]
and distance between the two will be (V+v)t