3kx = mg ==> x= mg/k .........
of lower spring is cut net force ==> mg + k(mg/k) = 2mg therfore accn =2g !!!!!!!!!!
a block of mass m is attached as shown .at equilibrium both the springs are compressed by same length if suddenly lower spring is cut. what is the accelaration of the block just after the spring is cut
-
UP 0 DOWN 0 0 2
2 Answers
1this diagram can be redrawn to resemble a parallel combination of springs.....
3