the answer given is (d) only...............plz post ur working didi ....so tht i can build some approach
A particle is observed from two frames s1 nd s2. The frame s2 moves wid respect to s1 wid an acceleration a .Let F1 nd F2 be the pseudo forces on the particle when seen from s1 nd s2 resp..which of the following r not possible::::::::
A.f1=0,f2≠0 B.f1≠0,f2=0
C.f1≠0,f2≠0 D.f1=0,f2=0 .........................
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5 Answers
ANS D
Becz if 1 frame is accelerating wrt the other then it can't be that both observe no pseudo force
It has to be that either one of these observe a pseudo force or both observe pseudo forces of different magnitudes
Consider the frames s1 and s2.
So imagine the initial position of the frames to be as in the diagram below.
======( S1)================================
<o>
=======( S2)===============================
Since both are accelerating, let the final positions of S1 and S2 be as in the diagram below :
================( S1)======================
<o>
==========================( S2)============
Case 1: Particle <o> is stationary.
There is a relative acceleration between the particle <o> and S1. So a (pseudo) force has to exist.
There is a relative acceleration between the particle and S2 also, so (pseudo) force has to exist.
Hence C is possible.
Case 2: Particle <o> is moving with acceleration equal to S1.
Here acceleration w.r.t S1 is 0 and w.r.t S2 there is some value of acceleration.
Hence F1 = 0, and F2 ≠0.
Case 3: Particle <o> is moving with acceleration equal to S2.
Here acceleration w.r.t S1 has some value whereas acceleration w.r.t S2 is 0.
Hence F1 ≠0 and F2 = 0.
So A and B are possible.
Hence the correct solution to this question is D
I have a reason why D is not possible.
It is given that the frames move at an acceleration with respect to each other, hence both frames have different accelerations. So the particle cannot exhibit two accelerations at the same time. Hence the relative accelerations w.r.t both frames cannot be zero.
Hence F1 ≠0 and F2 ≠0 situation is not possible. Hence solution D is only correct.
Hope you got the concepts right :)