1Radius of curvature at that instant is:
[ucos(q/2)]2g
A particle is projected with velocity u at an angle q with the horizontal . Find the radius of curvature of the parabola traced out by the particle at the point where velocity makes an angle q/2 with the horizontal.
plzz give the full soln....
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8 Answers
1hi friend in these ques you have to youse idea that
in circularl motin acc=v2/r where r is radius of curvature.
nw in this problem first you find velocity at that point yousing cocept that horizontal velocity remains same.
here acc g and v is perpendicular velocity (component ) to acc.
1@ujjwalkalra the xpressin radius of curvature should be
r = \frac{[1+(\frac{dy}{dx})^{2}]^{\frac{3}{2}}}{\frac{d^{2}y}{dx^{2}}}
1oops sorry yar in hurry i missed it..sory to all and thx euclid