106
FRom the FBD, we can see that
R,a cos30° = W = 50g
=> R,a = 500*2/√3
R,a sin30° = R,b
=> R,b = 500*4/√3
calc. errors possible
THE 50 KG HOMOGENOUS SMOOTH SPHERE RESTS ON THE 30 DEGREE IBCLINE A AND AGAINST SMOOTH VERTICAL WALL B.CALCULATE THE NORMAL FORCES AT A AND B.
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3 Answers
106
1
from this figure since vertically opposite angle hence so called 30° at A