ABHISHEK BACHHAN (T1)= 2d/√v2-u2
HRITWIK RAOUSHAN (T2) = (d/v-u) + (d/v+u)
HRITWIK RAOUSHAN takes more time as T1/T1 <1
- Akash Anand Excellent work ...try to post a crisp solution for this.Upvote·0· Reply ·2013-06-14 03:14:07
ABHISHEK BACHHAN (T1)= 2d/√v2-u2
HRITWIK RAOUSHAN (T2) = (d/v-u) + (d/v+u)
HRITWIK RAOUSHAN takes more time as T1/T1 <1
T1/T2= √v2-u2/v
squaring both sides,
(T1/T2)2 = 1-(u/v)2
Since, u<v , (u/v)<1 , So T1>T2
Am I Right?