resistive force

v_{x}=v_{o}cos\theta _{o}e^{(\frac{-kt}{m})}

v_{y}=v_{o}sin\theta _{o}e^{(\frac{-kt}{m})}+\frac{g}{k}[e^{(\frac{-kt}{m})}-1]?????????

bhaiya i am sorry i don't have the ans so i can't verify. give some hints to your working.

not sure abt the exact ans

but see , F=-kv

so find force F_x in x direction, and F_y in y direction . (dont forget gravity)

now write F_x = m a_x =m dv_x/dt

similarly for y direction .

same question is there in dc pandey so u can verify the answer.