ring and string

we have same tension in both parts ( as it is the same string)

cancelling forces in horizontal drirection

T+Tcosθ=mw²(3L)

Tsinθ=mg

dividing

(1+cosθ)/sinθ =w²(3L/g)

further cosθ=3/5 sinθ=4/5

2=w²(3L/10)

w²=20/3L

we get w and hence all the value of speed tension etc.

ROHAN

PLZ SEE THREAD TENSION!!!!!!!!!!!!!!..............THERE WE HAVE DISCUSSED......TENSION IN THE STRING!...........IT SHOULD BE DIFFERENT!

AFTER READING IT POST HERE!