rm

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find the ratio of magnitude of angular momentum of a rolling disk abt origin to that abt tne point O on the disk which is at a dist. R/2 frm the center..
1.2:1
2.1:1
3.1:3
4.4:3

#Physics #Mechanics

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maydayhay ·2009-04-05 08:49:45

ang momentum of rolling disc abt COM = ml²w/2

O is kahaan par? horizontally R/2 or where?

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vaishnavi bansal ·2009-04-05 08:52:53

perpendicularly above center at a dist R/2

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-05 08:54:22

b
angular mom= Iw

I for disc= MR^2/2

I for disc bout O =I com+MR^2/4

I com =MR^2/4
isse i gt b

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-05 08:57:39

really it also depnds on d axis wich u consider
if u consider verticla then u get d bove ansewr

if u consider horizontal then u egt answer as 1:2

so i guess vertical kara hoga consider

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vaishnavi bansal ·2009-04-05 09:00:40

pata nahi i donn know the ans....

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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