perpendicularly above center at a dist R/2
find the ratio of magnitude of angular momentum of a rolling disk abt origin to that abt tne point O on the disk which is at a dist. R/2 frm the center..
1.2:1
2.1:1
3.1:3
4.4:3
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5 Answers
maydayhay
·2009-04-05 08:49:45
ang momentum of rolling disc abt COM = ml2w/2
O is kahaan par? horizontally R/2 or where?
°ღ•๓ÑÏ…Î
·2009-04-05 08:54:22
b
angular mom= Iw
I for disc= MR^2/2
I for disc bout O =I com+MR^2/4
I com =MR^2/4
isse i gt b
°ღ•๓ÑÏ…Î
·2009-04-05 08:57:39
really it also depnds on d axis wich u consider
if u consider verticla then u get d bove ansewr
if u consider horizontal then u egt answer as 1:2
so i guess vertical kara hoga consider