PLS ALSO ASSUME ANY OTHER PARAMETERS THAT I HAVE NOT GIVEN (EXCEPT THE DIFFERENCE IN HEIGHT[3])
FIND THE DIFFERENCE IN WATER LEVELS IN THE CENTER OF THE TUBE AND THE CORNERS. TUBE IS ROTATED BY ANGULAR VELOCITY ω AND THE LIQUID HAS DENSITY OF Ï. [1]
Each of you must have done this sum atleast a 1000 times, but pls post the full solution.
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4 Answers
Anirudh Narayanan
·2009-01-27 17:30:30
Abhishek Priyam
·2009-01-28 02:32:06
now tending acc along surface is zero..
therefore..
ω2x.cosθ=g.sinθ
tanθ=ω2x
g
dy = ω2x
dx g
Solving it we get..
eqn of parabola...
yx=R=ΔH .... if center of tube is (0,0)
Is it alright..
Abhishek Priyam
·2009-01-28 02:44:56
another one on same concept...(a nice one.. :)
http://targetiit.com/iit_jee_forum/posts/fluids_1029.html