1061) KE of system = (assuming rod fixed at one end).
= 0.5*Ml2/3 * w22 + 0.5*mR2/2 * w12
2) KE of system = (assuming rod fixed at one end)
= 0.5*Ml2/3 * wo2 + 0.5*(mR2/2 + ml2) * wo2
A disk and a rod are hinged together in the following two ways:
1)through a pin joint
2)through welding at the hinge point
Given that in the first case the disk rotates with omega1 and rod rotates with omega2 .While in the second case the system rotates with a angular velocity omega0.
In both the above cases find the kinetic energy of the system.
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10 Answers
10611yup bhaiya i was also thinking of the same answer.According to me this question can also be solved through IOR.
49IOR ka zarurat kya hai when this can be solve this much easily??
haath me bramhaastra hai toh kya macchar ko bhi bramhaastra se maaroge??
33For clearing your concepts on writing energy in these kinds of situations see
http://targetiit.com/iit-jee-forum/posts/shm-doubts-3565.html
http://targetiit.com/iit-jee-forum/posts/30th-november-2008-762.html
23haath me bramhaastra hai toh kya macchar ko bhi bramhaastra se maaroge??
[9] [9][9][9][9][9]
49http://www.targetiit.com/iit-jee-forum/posts/rotation-instantaneous-centre-of-rotation-12434.html
mark the first para (with the hidden parts) carefully...
it says...It is a simple theory to make problems (of specific type) easier.........(if wisely used.....) :P
49but his name is quite fascinating..reflects his confidence and i like it!! :)
