rotation

A uniform solid sphere of mass m and radius R is kept on a long plank which is moving with acc. a= kt2 , where k = 1 m/s4 and t is time in seconds . There is no slipping b/w sphere and plank . The minimum value of coeff. of fricn. µ b/w plank and sphere so that sphere will slip at t=2s.

i hav formed the reqd. eqns but still stuck!!

i proceeded like this:

ac(acc. of center of sphere ) + Rα = a

f = 2/5 MRα

f ≤ µMg

but how to find ac??

1 Answers

23
qwerty ·

friction will act towards right

now f = mac

f = 2mRα5

5ac2 = Rα

accn of lowest pt = Rα + ac = 7ac2

fmax = μmg

hence (ac)max = μg
as the sphere shud sleep at t=4 , (ac)max shud occur at t = 4 , after that slipping starts

hence 7ac2 ≤ 4k , i.e 7μg2 ≤4k
μmin = 8k7g

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