rotation

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a particle is moving in a circular path of constant tangential acceleration time t after the beginning of motion the direction of net acceleration is at 30Â° to the radius vector at that instant The angular acceleration of the particle at that time t is

Please give the solution

#Physics #Mechanics

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2 Answers

33

Abhishek Priyam ·2009-02-04 00:14:47

Absurd reply... [3]

velocity of particle after time t (assuming at time t=0 v=0..)
v=at

now tang acc= a
radial acc= v²/R = (at)²/R

tan30Â°=a/((at)²/R)

1/√3=aR/a²t²=R/at²

a=√3R/t²..

lol.. :D

found anything interseing about it[3]

assumed a= const in begining (also use v=at for that..) and gave final acc as a function of time... :D

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11

Anirudh Narayanan ·2009-02-04 00:17:12

[9][9][9][9][9][9]

Interesting indeed!

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