1Fcos(alfa)-f=ma 1
fsin(alfa)+N=mg 2
f=Nu 3
also using equation of torque.....
fR-Fcos(alfa)*r=ymR2*(a/R) 4
solve dem nw....
a spool with thread wound on it, of mass 'm', rests on a rough horizontal surface. its moment of inertia relative to it sown axis is equal to I=γmR2 , where γ is a numerical factor, and R is the outside radius of the spool. The radius of the wound thread layer is equal to 'r'.
The spool is pulled without sliding by the thread with a constant force F directed at an nagle α (alpha) to the horizontal...
find:
a) projection of acceleration vector of the spool axis on the x-axis.
b) the work perfformed by the force F during the first 't' seconds afetr the beginning of motion.
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7 Answers
1
1can i know where has the component fsin(alpha) gone in taking the torque...plzzz explain me...
62I agree vaisnavi..
There has to be Fr nto F.rcos theta... :)
good that you looked at that mistake :)
1sry but m still confused can u plzz explain me that equation?