a disc of mass M and radius R can rotate freely about a horizontal shaft at S distant r from the centre of mass of the disc 0.the disc is released from postion shown figure,its angular acceleration will be
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UP 0 DOWN 0 0 1
1 Answers
Lokesh Verma
·2009-03-08 22:14:10
this is not that tough
moment of inertia about S will be
MR2/2+mr2
force acting is mg.
torque about S is mgr
torque is Iα
Equate you are done :)