0.4g?
4 Answers
Yes, I had been making a mistake.
Consider the ring with the point mass as the system. The net force acting on it is 2mg-N at the time of release. Now, 2mg-N=2maCOM. From the centre of the ring, the only torque is Rmg acting on the point mass. Now, Rmg=Iα=2mR2α ie g=2Rα.
The centre of mass is always at the mid-point of the centre of the ring and the position of the point mass. So, aCOM=R2α.
From this, we can get the value of N as 32mg.
No, it will be 43mg. Is it correct now?
- Niraj kumar Jha No ,the ans is 3mg/2
Upvote·0· Reply ·2013-09-16 08:45:44
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