1wait ,let me check up with the key.
In figure,there are shown two similar,uniform,rigid rods A and B each of mass M and length L are placed in contact at their one ends,on a smooth horizontal table.A sharp impulse is applied at one end of the rod A as
shown in the figure.Calculate the angular velocity of the rod A just after the impulse when rod A leaves off its contact from rod B.
The options are
(a) 6I/(5ML)
(b) 8I/(5ML)
(c) 18I/(5ML)
(d) 5I/(18ML)
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18 Answers
3see take ther com of the rods ...................find the horizontal distance of that from I.....call it d.................Id = (moi)rod about com*w .......................find w!!!!!!!!!
1... not able to solve !!.. doubt is whether the vertical rod will slide finally ?
62Hint:
1) An impulse will act at the a single point between A and B
2) The CM of the system will move according to I only
To be true i havent tried to one.. but if none of u can i will definitely try to solve this one :)