rotational(HCV)

JEE Mains 2015 Discussion Forum › Mechanics questions › rotational(HCV)

pulley's radius is 20cm and M.I is 0.2kgm² .the string is attached to a block. spring constant is 50 N/m .mass of block=1kg.The system is released from rest with spring at its natural length .Find speed of the block when it has descended through 10cm.take g=10m/s²

#Physics #Mechanics

UP 0 DOWN 0 0 5
Post on FacebookPost anonymously?

5 Answers

1

niteen9128 ·2010-01-16 04:24:08

is there any way other than energy conservation to solve this problem??

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

Jagaran Chowdhury ·2010-01-16 06:21:25

u can solve this using force equations(newtons second law of motion) but that is very difficult . conservation of energy is the best and easiest method to solve this.

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

niteen9128 ·2010-01-16 06:55:24

i got the answer by conservation of energy.....
but
i thoght of trying something.....as
cant we do something like
T=IÎ±=F_netr
in this case??

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

pratik123 agrawal ·2010-01-31 07:00:20

_{pratik ha ha}

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

pratik123 agrawal ·2010-01-31 07:04:24

_{pratik ha ha}

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω