rotational(HCV)

JEE Advanced 2015 Guidance › Mechanics questions › rotational(HCV)

pulley's radius is 20cm and M.I is 0.2kgm² .the string is attached to a block. spring constant is 50 N/m .mass of block=1kg.The system is released from rest with spring at its natural length .Find speed of the block when it has descended through 10cm.take g=10m/s²

#Physics #Mechanics

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5 Answers

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niteen9128 ·2010-01-16 04:24:08

is there any way other than energy conservation to solve this problem??

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Jagaran Chowdhury ·2010-01-16 06:21:25

u can solve this using force equations(newtons second law of motion) but that is very difficult . conservation of energy is the best and easiest method to solve this.

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niteen9128 ·2010-01-16 06:55:24

i got the answer by conservation of energy.....
but
i thoght of trying something.....as
cant we do something like
T=IÎ±=F_netr
in this case??

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pratik123 agrawal ·2010-01-31 07:00:20

_{pratik ha ha}

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pratik123 agrawal ·2010-01-31 07:04:24

_{pratik ha ha}

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