Rotational Mechanics

6 Answers

591
Akshay Ginodia ·

(A) ?

283
Sahil Jain ·

(A)

283
Sahil Jain ·

Ans is 15f/14m

466
Himanshu Giria ·

(A) ??

481
Anurag Ghosh ·

Sir what is the answer of this?

283
Sahil Jain ·

Friction will act forwrd
FOR TRANSLATION MOTION
F+fs= ma
For rotational motion
Fr/2 - fsr=Ia/r
solving we get a= 15F/14M
at the top most point linear accl is forward and rotn accl is also forward
there is no slipping
αr=a
so at the top most point total accl is
2a = 15F/7M

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