Rotational Motion

IIT JEE 2015 Forum › Mechanics questions › Rotational Motion

A rod and a block are of same mass. Initially rod is in horizontal position. What will be acceleration of tip of the rod when system is released from the position.

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#Physics #Mechanics

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6 Answers

Subhomoy Bakshi ·2010-03-20 12:17:45

i am getting g/6

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Tapas Gandhi ·2010-03-20 12:19:47

thats incorrect...

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Subhomoy Bakshi ·2010-03-20 12:29:48

3g/8

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Subhomoy Bakshi ·2010-03-20 12:30:10

thnx 4 verifying!!

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Kalyan IIT-K Beware I'm coming ·2010-03-20 13:15:44

here have we to find alpha at the end of the rod??

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Subhomoy Bakshi ·2010-03-20 13:24:42

for the hanging mass,
balancing forces,
we get!! mg-T=ma

so for the string, T=mg-ma

for rod, balancing forces,
mg=T+R

for rod balancing torque abt hinge
T.L-mg.L2=I.Î±
or, (mg-ma)L-mg.L2=13mL².aL
or, mg-ma-12mg=13ma
or, 12mg=43ma

giving, a=38g

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Rotational Motion

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