actuaaly i donn know the ans...so i cant tell anything....buh i think its right
a small partical of mass m n its restraining cord r spinning with an angular velocity ω on the horizontal surface of a smooth disc as shown..the force F is slightly relaxed , r increases n ω changes. 1.∂ω/∂r=-ω/r 2.∂ω/∂r=-2ω/r 3.∂ω/∂r=ω/r 4.∂ω/∂r=2ω/r
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3 Answers
Lokesh Verma
·Apr 5 '09 at 8:35
i think what you mean is F=mω2r
mass is constant and
∂F=m2ω∂ωr + m ω2 ∂r
since the force is not changed.. It is relaxed and brought back.. if i understood it correctly!
m2ω∂ωr + m ω2 ∂r =0
∂ω/∂r = - ω/2r
doesnt seem like i am getting anything good! :(
vaishnavi bansal
·Apr 5 '09 at 8:39
kaymant
·Apr 8 '09 at 11:49
The angular momentum about the center of the circle must remain constant. So that
Taking differentials, we get
which gives